What is 4x^2-16x+y^2+2y+13=0 ?

The solution to 4x^2-16x+y^2+2y+13=0 is Ellipse with (h,k)=(2,-1),a=1,b=2

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4x^2-16x+y^2+2y+13=0

4 x^{2} - 16 x + y^{2} + 2 y + 13 = 0

(h, k) = (2, - 1), a = 1, b = 2

Solution steps

4 x^{2} - 16 x + y^{2} + 2 y + 13 = 0

Rewrite

4 x^{2} - 16 x + y^{2} + 2 y + 13 = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{1 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 1), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, - 1), b = 2, a = 1

What is 4x^2-16x+y^2+2y+13=0 ?
The solution to 4x^2-16x+y^2+2y+13=0 is Ellipse with (h,k)=(2,-1),a=1,b=2