((x+1)^2)/(25)+((y+2)^2)/(49)=1

Lösung

\frac{( x + 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{49} = 1

(h, k) = (- 1, - 2), a = 5, b = 7

Schritte zur Lösung

\frac{( x + 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{49} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{5 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, - 2), a = 5, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, - 2), b = 7, a = 5

9 x^{2} + 4 y^{2} + 18 x - 8 y - 23 = 0

9 (x - 3)^{2} + 4 (y - 4)^{2} = 36

\frac{( x - 7 ) ^{2}}{3} + \frac{( y + 11 ) ^{2}}{5} = 1

20 x^{2} + 4 y^{2} = 5

\frac{( x - 5 ) ^{2}}{12} + \frac{( y + 2 ) ^{2}}{16} = 1