What is ((x+0)^2)/(225/25)+((y-1)^2)/(225/9)=1 ?

The solution to ((x+0)^2)/(225/25)+((y-1)^2)/(225/9)=1 is Ellipse with (h,k)=(0,1),a=3,b=5

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((x+0)^2)/(225/25)+((y-1)^2)/(225/9)=1

\frac{( x + 0 ) ^{2}}{\frac{225}{25}} + \frac{( y - 1 ) ^{2}}{\frac{225}{9}} = 1

(h, k) = (0, 1), a = 3, b = 5

Solution steps

\frac{( x + 0 ) ^{2}}{\frac{225}{25}} + \frac{( y - 1 ) ^{2}}{\frac{225}{9}} = 1

Rewrite

\frac{( x + 0 ) ^{2}}{\frac{225}{25}} + \frac{( y - 1 ) ^{2}}{\frac{225}{9}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 1 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 1), a = 3, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 1), b = 5, a = 3

What is ((x+0)^2)/(225/25)+((y-1)^2)/(225/9)=1 ?
The solution to ((x+0)^2)/(225/25)+((y-1)^2)/(225/9)=1 is Ellipse with (h,k)=(0,1),a=3,b=5