What is ((x-1)^2)/3+((y)^2)/4 =1 ?

The solution to ((x-1)^2)/3+((y)^2)/4 =1 is Ellipse with (h,k)=(1,0),a=sqrt(3),b=2

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((x-1)^2)/3+((y)^2)/4 =1

\frac{( x - 1 ) ^{2}}{3} + \frac{( y ) ^{2}}{4} = 1

(h, k) = (1, 0), a = 3, b = 2

Solution steps

\frac{( x - 1 ) ^{2}}{3} + \frac{y ^{2}}{4} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{3} + \frac{y ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{( 3 ) ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 0), a = 3, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, 0), b = 2, a = 3

\frac{100}{1 + x ^{2} + 2 y ^{2}} = 2

\frac{( x + 0 ) ^{2}}{\frac{225}{25}} + \frac{( y - 1 ) ^{2}}{\frac{225}{9}} = 1

3 = x^{2} + 9 y^{2}

\frac{( x - 1 ) ^{2}}{16} + \frac{y ^{2}}{9} = 1

\frac{( x - 1 ) ^{2}}{4} + \frac{( y + 1 ) ^{2}}{9} = 1

What is ((x-1)^2)/3+((y)^2)/4 =1 ?
The solution to ((x-1)^2)/3+((y)^2)/4 =1 is Ellipse with (h,k)=(1,0),a=sqrt(3),b=2