What is ((x-2)^2)/4+y^2=1 ?

The solution to ((x-2)^2)/4+y^2=1 is Ellipse with (h,k)=(2,0),a=2,b=1

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((x-2)^2)/4+y^2=1

\frac{( x - 2 ) ^{2}}{4} + y^{2} = 1

(h, k) = (2, 0), a = 2, b = 1

Solution steps

\frac{( x - 2 ) ^{2}}{4} + y^{2} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{4} + y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 0), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, 0), a = 2, b = 1

\frac{x}{( x ^{2} + y ^{2} )} = \frac{3}{2}

\frac{( x + 2 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{12} = 1

2 x^{2} + y^{2} + 10 x + 12 y = - 12

\frac{x ^{2}}{15} + \frac{y ^{2}}{4} = 1

5 x^{2} + y^{2} = 25

What is ((x-2)^2)/4+y^2=1 ?
The solution to ((x-2)^2)/4+y^2=1 is Ellipse with (h,k)=(2,0),a=2,b=1