What is ((x+1.23)^2)/(1.59^2)+(y^2)/(1.01^2)=1 ?

The solution to ((x+1.23)^2)/(1.59^2)+(y^2)/(1.01^2)=1 is Ellipse with (h,k)=(-1.23,0),a=1.59,b=1.01

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((x+1.23)^2)/(1.59^2)+(y^2)/(1.01^2)=1

\frac{( x + 1.23 ) ^{2}}{1.5 9 ^{2}} + \frac{y ^{2}}{1.0 1 ^{2}} = 1

(h, k) = (- 1.23, 0), a = 1.59, b = 1.01

Solution steps

\frac{( x + 1.23 ) ^{2}}{1.5 9 ^{2}} + \frac{y ^{2}}{1.0 1 ^{2}} = 1

Rewrite

\frac{( x + 1.23 ) ^{2}}{1.5 9 ^{2}} + \frac{y ^{2}}{1.0 1 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1.23 ) ) ^{2}}{1.5 9 ^{2}} + \frac{( y - 0 ) ^{2}}{1.0 1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1.23, 0), a = 1.59, b = 1.01

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1.23, 0), a = 1.59, b = 1.01

What is ((x+1.23)^2)/(1.59^2)+(y^2)/(1.01^2)=1 ?
The solution to ((x+1.23)^2)/(1.59^2)+(y^2)/(1.01^2)=1 is Ellipse with (h,k)=(-1.23,0),a=1.59,b=1.01