What is (x^2)/(4900)+(y^2)/(2500)=1 ?

The solution to (x^2)/(4900)+(y^2)/(2500)=1 is Ellipse with (h,k)=(0,0),a=70,b=50

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(x^2)/(4900)+(y^2)/(2500)=1

\frac{x ^{2}}{4900} + \frac{y ^{2}}{2500} = 1

(h, k) = (0, 0), a = 70, b = 50

Solution steps

\frac{x ^{2}}{4900} + \frac{y ^{2}}{2500} = 1

Rewrite

\frac{x ^{2}}{4900} + \frac{y ^{2}}{2500} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 0 ^{2}} + \frac{( y - 0 ) ^{2}}{5 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 70, b = 50

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 70, b = 50

x^{2} + y^{2} - \frac{21}{8} x + \frac{19}{4} - \frac{525}{8} = 0

2 x^{2} - 8 x + y^{2} - 4 y + 8 = 0

25 x^{2} + 16 y^{2} + 200 x + 64 y + 64 = 0

27 x^{2} + 48 y^{2} - 54 x - 192 y - 213 = 0

x^{2} + 16 y^{2} - 4 x - 128 y + 244 = 0

What is (x^2)/(4900)+(y^2)/(2500)=1 ?
The solution to (x^2)/(4900)+(y^2)/(2500)=1 is Ellipse with (h,k)=(0,0),a=70,b=50