What is (y^2)/(16)-(x^2)/(25)=1 ?

The solution to (y^2)/(16)-(x^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=4,b=5

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(y^2)/(16)-(x^2)/(25)=1

\frac{y ^{2}}{16} - \frac{x ^{2}}{25} = 1

(h, k) = (0, 0), a = 4, b = 5

Solution steps

\frac{y ^{2}}{16} - \frac{x ^{2}}{25} = 1

Rewrite

\frac{y ^{2}}{16} - \frac{x ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{4 ^{2}} - \frac{( x - 0 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 5

\frac{x ^{2}}{64} - \frac{y ^{2}}{36} = 1

9 x^{2} - 4 y^{2} - 90 x - 32 y = - 305

36 x^{2} + 288 x + 64 y^{2} - 256 y = 1472

\frac{y ^{2}}{4} - (x + 1)^{2} = 1

y^{2} - 4 y - 8 x - 12 = 0

What is (y^2)/(16)-(x^2)/(25)=1 ?
The solution to (y^2)/(16)-(x^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=4,b=5