What is 4x^2+9y^2-16x-54y+61=0 ?

The solution to 4x^2+9y^2-16x-54y+61=0 is Ellipse with (h,k)=(2,3),a=3,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2+9y^2-16x-54y+61=0

4 x^{2} + 9 y^{2} - 16 x - 54 y + 61 = 0

(h, k) = (2, 3), a = 3, b = 2

Solution steps

4 x^{2} + 9 y^{2} - 16 x - 54 y + 61 = 0

Rewrite

4 x^{2} + 9 y^{2} - 16 x - 54 y + 61 = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{3 ^{2}} + \frac{( y - 3 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 3), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, 3), a = 3, b = 2

9 x^{2} + 25 y^{2} - 100 y - 125 = 0

x^{2} + 4 y^{2} + 10 x + 10 y - 8 = 0

16 x^{2} + 25 y^{2} - 96 x + 50 y - 231 = 0

(\frac{x ^{2}}{15}) + (\frac{y ^{2}}{16}) = 1

\frac{x ^{2}}{25} + \frac{z ^{2}}{64} = 1

What is 4x^2+9y^2-16x-54y+61=0 ?
The solution to 4x^2+9y^2-16x-54y+61=0 is Ellipse with (h,k)=(2,3),a=3,b=2