What is 16x^2+25y^2-1600=0 ?

The solution to 16x^2+25y^2-1600=0 is Ellipse with (h,k)=(0,0),a=10,b=8

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16x^2+25y^2-1600=0

16 x^{2} + 25 y^{2} - 1600 = 0

(h, k) = (0, 0), a = 10, b = 8

Solution steps

16 x^{2} + 25 y^{2} - 1600 = 0

Rewrite

16 x^{2} + 25 y^{2} - 1600 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 0 ^{2}} + \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10, b = 8

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10, b = 8

What is 16x^2+25y^2-1600=0 ?
The solution to 16x^2+25y^2-1600=0 is Ellipse with (h,k)=(0,0),a=10,b=8