What is 0=4-x^2-2y^2 ?

The solution to 0=4-x^2-2y^2 is Ellipse with (h,k)=(0,0),a=2,b=sqrt(2)

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0=4-x^2-2y^2

0 = 4 - x^{2} - 2 y^{2}

(h, k) = (0, 0), a = 2, b = 2

Solution steps

0 = 4 - x^{2} - 2 y^{2}

Rewrite

0 - 4 + x^{2} + 2 y^{2} = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 2

25 x^{(2)} + 4 y^{(2)} = 100

x^{2} 64 + y^{2} 49 = 1

3 x^{2} + 2 y^{2} = 8

\frac{( x + 1 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{25} = 1

\frac{x ^{2}}{256} + \frac{y ^{2}}{400} = 1

What is 0=4-x^2-2y^2 ?
The solution to 0=4-x^2-2y^2 is Ellipse with (h,k)=(0,0),a=2,b=sqrt(2)