What is (x^2)/(25)+((y-3)^2)/(16)=1 ?

The solution to (x^2)/(25)+((y-3)^2)/(16)=1 is Ellipse with (h,k)=(0,3),a=5,b=4

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(x^2)/(25)+((y-3)^2)/(16)=1

\frac{x ^{2}}{25} + \frac{( y - 3 ) ^{2}}{16} = 1

(h, k) = (0, 3), a = 5, b = 4

Solution steps

\frac{x ^{2}}{25} + \frac{( y - 3 ) ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{( y - 3 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 3 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 3), a = 5, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 3), a = 5, b = 4

What is (x^2)/(25)+((y-3)^2)/(16)=1 ?
The solution to (x^2)/(25)+((y-3)^2)/(16)=1 is Ellipse with (h,k)=(0,3),a=5,b=4