What is (x^2)/(49)+(y^2)/(169)=1 ?

The solution to (x^2)/(49)+(y^2)/(169)=1 is Ellipse with (h,k)=(0,0),a=7,b=13

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(x^2)/(49)+(y^2)/(169)=1

\frac{x ^{2}}{49} + \frac{y ^{2}}{169} = 1

(h, k) = (0, 0), a = 7, b = 13

Solution steps

\frac{x ^{2}}{49} + \frac{y ^{2}}{169} = 1

Rewrite

\frac{x ^{2}}{49} + \frac{y ^{2}}{169} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{1 3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 13

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 13, a = 7

(- y - 6)^{2} + 8 x^{2} = 64

4 x^{2} + 24 x + 25 y^{2} + 200 y + 336 = 0

3 (x + 1)^{2} + (y - 1)^{2} = 6

\frac{x ^{2} + y ^{2} - x}{2 x - x ^{2} - y ^{2}} = 0

7 x^{2} + 16 y^{2} - 14 x - 64 y - 41 = 0

What is (x^2)/(49)+(y^2)/(169)=1 ?
The solution to (x^2)/(49)+(y^2)/(169)=1 is Ellipse with (h,k)=(0,0),a=7,b=13