What is 2x^2+y^2-10=0 ?

The solution to 2x^2+y^2-10=0 is Ellipse with (h,k)=(0,0),a=sqrt(5),b=sqrt(10)

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2x^2+y^2-10=0

2 x^{2} + y^{2} - 10 = 0

(h, k) = (0, 0), a = 5, b = 10

Solution steps

2 x^{2} + y^{2} - 10 = 0

Rewrite

2 x^{2} + y^{2} - 10 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 5 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 10 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 10

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 10, a = 5

3 x^{2} + 3 y^{2} + 12 y = 0

\frac{( x + 1 ) ^{2}}{22.33} + \frac{( y - 1 ) ^{2}}{16.75} = 1

\frac{x ^{2}}{25} + \frac{y ^{2}}{11} = 1

4 x^{2} + 2 y^{2} - 7 x + y - 5 = 0

225 x^{2} + 289 y^{2} = 65.025

What is 2x^2+y^2-10=0 ?
The solution to 2x^2+y^2-10=0 is Ellipse with (h,k)=(0,0),a=sqrt(5),b=sqrt(10)