What is ((x^2)/(15))+((((y-8))/(49))^2)=1 ?

The solution to ((x^2)/(15))+((((y-8))/(49))^2)=1 is Ellipse with (h,k)=(0,8),a=sqrt(15),b=49

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((x^2)/(15))+((((y-8))/(49))^2)=1

(\frac{x ^{2}}{15}) + ((\frac{( y - 8 )}{49})^{2}) = 1

(h, k) = (0, 8), a = 15, b = 49

Solution steps

\frac{x ^{2}}{15} + (\frac{y - 8}{49})^{2} = 1

Rewrite

\frac{x ^{2}}{15} + (\frac{y - 8}{49})^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 15 ) ^{2}} + \frac{( y - 8 ) ^{2}}{4 9 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 8), a = 15, b = 49

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 8), b = 49, a = 15

100 - 25 x^{2} - 4 y^{2} \geq 0

(\frac{x - 3}{2})^{2} + (y - 7)^{2} = 5^{2}

8 x^{2} + 28 y^{2} = 112

\frac{x ^{2}}{9} + \frac{( y + 3 ) ^{2}}{16} = 1

16 x^{2} + 9 y^{2} - 96 x + 36 y - 36 = 0

What is ((x^2)/(15))+((((y-8))/(49))^2)=1 ?
The solution to ((x^2)/(15))+((((y-8))/(49))^2)=1 is Ellipse with (h,k)=(0,8),a=sqrt(15),b=49