What is 2x^2+8y^2=16 ?

The solution to 2x^2+8y^2=16 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=sqrt(2)

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2x^2+8y^2=16

2 x^{2} + 8 y^{2} = 16

(h, k) = (0, 0), a = 22, b = 2

Solution steps

2 x^{2} + 8 y^{2} = 16

Rewrite

2 x^{2} + 8 y^{2} = 16

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 22, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 22, b = 2

What is 2x^2+8y^2=16 ?
The solution to 2x^2+8y^2=16 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=sqrt(2)