What is 16x^2+9y^2-100=0 ?

The solution to 16x^2+9y^2-100=0 is Ellipse with (h,k)=(0,0),a= 5/2 ,b= 10/3

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16x^2+9y^2-100=0

16 x^{2} + 9 y^{2} - 100 = 0

(h, k) = (0, 0), a = \frac{5}{2}, b = \frac{10}{3}

Solution steps

16 x^{2} + 9 y^{2} - 100 = 0

Rewrite

16 x^{2} + 9 y^{2} - 100 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{5}{2} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{10}{3} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{5}{2}, b = \frac{10}{3}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = \frac{10}{3}, a = \frac{5}{2}

What is 16x^2+9y^2-100=0 ?
The solution to 16x^2+9y^2-100=0 is Ellipse with (h,k)=(0,0),a= 5/2 ,b= 10/3