What is 2x^2+3y^2+12x-24y+60=0 ?

The solution to 2x^2+3y^2+12x-24y+60=0 is Ellipse with (h,k)=(-3,4),a=sqrt(3),b=sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

2x^2+3y^2+12x-24y+60=0

2 x^{2} + 3 y^{2} + 12 x - 24 y + 60 = 0

(h, k) = (- 3, 4), a = 3, b = 2

Solution steps

2 x^{2} + 3 y^{2} + 12 x - 24 y + 60 = 0

Rewrite

2 x^{2} + 3 y^{2} + 12 x - 24 y + 60 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 3 ) ) ^{2}}{( 3 ) ^{2}} + \frac{( y - 4 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 3, 4), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 3, 4), a = 3, b = 2

What is 2x^2+3y^2+12x-24y+60=0 ?
The solution to 2x^2+3y^2+12x-24y+60=0 is Ellipse with (h,k)=(-3,4),a=sqrt(3),b=sqrt(2)