What is 2x^2+5y^2=10 ?

The solution to 2x^2+5y^2=10 is Ellipse with (h,k)=(0,0),a=sqrt(5),b=sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

2x^2+5y^2=10

2 x^{2} + 5 y^{2} = 10

(h, k) = (0, 0), a = 5, b = 2

Solution steps

2 x^{2} + 5 y^{2} = 10

Rewrite

2 x^{2} + 5 y^{2} = 10

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 5 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5, b = 2

What is 2x^2+5y^2=10 ?
The solution to 2x^2+5y^2=10 is Ellipse with (h,k)=(0,0),a=sqrt(5),b=sqrt(2)