What is x^2+((y-4)^2)/4 =1 ?

The solution to x^2+((y-4)^2)/4 =1 is Ellipse with (h,k)=(0,4),a=1,b=2

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x^2+((y-4)^2)/4 =1

x^{2} + \frac{( y - 4 ) ^{2}}{4} = 1

(h, k) = (0, 4), a = 1, b = 2

Solution steps

x^{2} + \frac{( y - 4 ) ^{2}}{4} = 1

Rewrite

x^{2} + \frac{( y - 4 ) ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 4 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 4), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 4), b = 2, a = 1

What is x^2+((y-4)^2)/4 =1 ?
The solution to x^2+((y-4)^2)/4 =1 is Ellipse with (h,k)=(0,4),a=1,b=2