x^2+4x+m(x)-1=0

Lösung

x^{2} + 4 x + m (x) - 1 = 0

(h, k) = (- 2, 5), p = - \frac{1}{4}

Schritte zur Lösung

x^{2} + 4 x + y - 1 = 0

Rewrite

x^{2} + 4 x + y - 1 = 0

in the standard form

4 (- \frac{1}{4}) (y - 5) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 5), p = - \frac{1}{4}