What is ((x-2)^2)/(20)+(y^2)/(36)=1 ?

The solution to ((x-2)^2)/(20)+(y^2)/(36)=1 is Ellipse with (h,k)=(2,0),a=2sqrt(5),b=6

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((x-2)^2)/(20)+(y^2)/(36)=1

\frac{( x - 2 ) ^{2}}{20} + \frac{y ^{2}}{36} = 1

(h, k) = (2, 0), a = 25, b = 6

Solution steps

\frac{( x - 2 ) ^{2}}{20} + \frac{y ^{2}}{36} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{20} + \frac{y ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{( 2 5 ) ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 0), a = 25, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, 0), b = 6, a = 25

6 x^{2} + 9 y^{2} - 18 y - 45 = 0

\frac{( X - 1 ) ^{2}}{4} + \frac{( Y + 2 ) ^{2}}{16} = 1

4 x^{2} + 25 y^{2} - 50 y = 75

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

5 x^{2} + 9 y^{2} = 45

What is ((x-2)^2)/(20)+(y^2)/(36)=1 ?
The solution to ((x-2)^2)/(20)+(y^2)/(36)=1 is Ellipse with (h,k)=(2,0),a=2sqrt(5),b=6