What is (-2y-3)^2=-5(-3x-2) ?

The solution to (-2y-3)^2=-5(-3x-2) is Parabola with (h,k)=(-2/3 ,-3/2),p= 15/16

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(-2y-3)^2=-5(-3x-2)

(- 2 y - 3)^{2} = - 5 (- 3 x - 2)

(h, k) = (- \frac{2}{3}, - \frac{3}{2}), p = \frac{15}{16}

Solution steps

(- 2 y - 3)^{2} = - 5 (- 3 x - 2)

Rewrite

(- 2 y - 3)^{2} = - 5 (- 3 x - 2)

in the standard form:

4 \cdot \frac{15}{16} (x - (- \frac{2}{3})) = (y - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{2}{3}, - \frac{3}{2}), p = \frac{15}{16}

- 3 x^{2} + y + 2 = 0

2 y^{2} = 3 x

x + (y - 4)^{2} = 0

y^{2} = \frac{1}{2} x

(x + 2)^{2} = 12 (y - 2)

What is (-2y-3)^2=-5(-3x-2) ?
The solution to (-2y-3)^2=-5(-3x-2) is Parabola with (h,k)=(-2/3 ,-3/2),p= 15/16