What is 9x^2+49y^2=441 ?

The solution to 9x^2+49y^2=441 is Ellipse with (h,k)=(0,0),a=7,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

9x^2+49y^2=441

9 x^{2} + 49 y^{2} = 441

(h, k) = (0, 0), a = 7, b = 3

Solution steps

9 x^{2} + 49 y^{2} = 441

Rewrite

9 x^{2} + 49 y^{2} = 441

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 7, b = 3

What is 9x^2+49y^2=441 ?
The solution to 9x^2+49y^2=441 is Ellipse with (h,k)=(0,0),a=7,b=3