What is 9x^2+4y^2=25 ?

The solution to 9x^2+4y^2=25 is Ellipse with (h,k)=(0,0),a= 5/3 ,b= 5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

9x^2+4y^2=25

9 x^{2} + 4 y^{2} = 25

(h, k) = (0, 0), a = \frac{5}{3}, b = \frac{5}{2}

Solution steps

9 x^{2} + 4 y^{2} = 25

Rewrite

9 x^{2} + 4 y^{2} = 25

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{5}{3} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{5}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{5}{3}, b = \frac{5}{2}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = \frac{5}{2}, a = \frac{5}{3}

What is 9x^2+4y^2=25 ?
The solution to 9x^2+4y^2=25 is Ellipse with (h,k)=(0,0),a= 5/3 ,b= 5/2