What is ((x-6)^2)/(36)+((y+1)^2)/(25)=1 ?

The solution to ((x-6)^2)/(36)+((y+1)^2)/(25)=1 is Ellipse with (h,k)=(6,-1),a=6,b=5

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((x-6)^2)/(36)+((y+1)^2)/(25)=1

\frac{( x - 6 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

(h, k) = (6, - 1), a = 6, b = 5

Solution steps

\frac{( x - 6 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

Rewrite

\frac{( x - 6 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 6 ) ^{2}}{6 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (6, - 1), a = 6, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (6, - 1), a = 6, b = 5

What is ((x-6)^2)/(36)+((y+1)^2)/(25)=1 ?
The solution to ((x-6)^2)/(36)+((y+1)^2)/(25)=1 is Ellipse with (h,k)=(6,-1),a=6,b=5