What is (y-(-2))^2=2(2)(x-(-1)) ?

The solution to (y-(-2))^2=2(2)(x-(-1)) is Parabola with (h,k)=(-1,-2),p=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y-(-2))^2=2(2)(x-(-1))

(y - (- 2))^{2} = 2 (2) (x - (- 1))

(h, k) = (- 1, - 2), p = 1

Solution steps

(y - (- 2))^{2} = 2 \cdot 2 (x - (- 1))

Rewrite

(y - (- 2))^{2} = 2 \cdot 2 (x - (- 1))

in the standard form:

4 \cdot 1 \cdot (x - (- 1)) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 2), p = 1

- 6 y - 2 x^{2} = 0

x^{2} + 2 x + y - 1 = 0

y^{2} - 12 y - 4 x = - 28

2 y^{2} - 2 x - 4 y + 3 = 0

(x - 1)^{2} = - 8 (y - 4)

What is (y-(-2))^2=2(2)(x-(-1)) ?
The solution to (y-(-2))^2=2(2)(x-(-1)) is Parabola with (h,k)=(-1,-2),p=1