kreisumfang x^2+y^2-18x-6y-10=0

Lösung

kreisumfang

x^{2} + y^{2} - 18 x - 6 y - 10 = 0

C = 20 π

Schritte zur Lösung

C = 2 π r

Finde den Radius

Radius given

x^{2} + y^{2} - 18 x - 6 y - 10 = 0 : r = 10

C = 2 π 10

Fasse zusammen

C = 20 π

c i rc u m f ere n ce x^{2} + y^{2} = 2.5

c i rc u m f ere n ce x^{2} + y^{2} + 2 x - 2 y = 0

c i rc u m f ere n ce x^{2} + y^{2} + x + 3 y - 104 = 0

c i rc u m f ere n ce 6 x^{2} + 6 y^{2} = 12 x + 12 y + 6

c i rc u m f ere n ce x^{2} + y^{2} + 6 x - 4 y - 12 = 0