What is the radius 3x^2-12x-18y+3y^2=0 ?

The radius 3x^2-12x-18y+3y^2=0 is r=sqrt(13)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

radius 3x^2-12x-18y+3y^2=0

radius

r = 13

Solution steps

3 x^{2} - 12 x - 18 y + 3 y^{2} = 0

Rewrite

3 x^{2} - 12 x - 18 y + 3 y^{2} = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - 3)^{2} = (13)^{2}

Therefore the circle properties are:

(a, b) = (2, 3), r = 13

And the radius is:

r = 13

What is the radius 3x^2-12x-18y+3y^2=0 ?
The radius 3x^2-12x-18y+3y^2=0 is r=sqrt(13)