What is the radius (x-1)^2+(y-3)^2=16 ?

The radius (x-1)^2+(y-3)^2=16 is r=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

radius (x-1)^2+(y-3)^2=16

radius

r = 4

Solution steps

(x - 1)^{2} + (y - 3)^{2} = 16

Rewrite

(x - 1)^{2} + (y - 3)^{2} = 16

in the form of the standard circle equation

(x - 1)^{2} + (y - 3)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, 3), r = 4

And the radius is:

r = 4