What is the radius x^2+y^2+9x-9y-17=0 ?

The radius x^2+y^2+9x-9y-17=0 is r=sqrt(115/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

radius x^2+y^2+9x-9y-17=0

radius

r = \frac{115}{2}

Solution steps

x^{2} + y^{2} + 9 x - 9 y - 17 = 0

Rewrite

x^{2} + y^{2} + 9 x - 9 y - 17 = 0

in the form of the standard circle equation

(x - (- \frac{9}{2}))^{2} + (y - \frac{9}{2})^{2} = (\frac{115}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{9}{2}, \frac{9}{2}), r = \frac{115}{2}

And the radius is:

r = \frac{115}{2}

What is the radius x^2+y^2+9x-9y-17=0 ?
The radius x^2+y^2+9x-9y-17=0 is r=sqrt(115/2)