What is the radius 6(x-3)^2+6(y+7)^2=216 ?

The radius 6(x-3)^2+6(y+7)^2=216 is r=6

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radius 6(x-3)^2+6(y+7)^2=216

radius

r = 6

Solution steps

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

Rewrite

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 7))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (3, - 7), r = 6

And the radius is:

r = 6

What is the radius 6(x-3)^2+6(y+7)^2=216 ?
The radius 6(x-3)^2+6(y+7)^2=216 is r=6