What is the radius (x+4)^2+(y-3)^2=4 ?

The radius (x+4)^2+(y-3)^2=4 is r=2

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radius (x+4)^2+(y-3)^2=4

radius

r = 2

Solution steps

(x + 4)^{2} + (y - 3)^{2} = 4

Rewrite

(x + 4)^{2} + (y - 3)^{2} = 4

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 4, 3), r = 2

And the radius is:

r = 2