What is 16y^2+8y-24x+49=0 ?

The solution to 16y^2+8y-24x+49=0 is Parabola with (h,k)=(2,-1/4),p= 3/8

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16y^2+8y-24x+49=0

16 y^{2} + 8 y - 24 x + 49 = 0

(h, k) = (2, - \frac{1}{4}), p = \frac{3}{8}

Solution steps

16 y^{2} + 8 y - 24 x + 49 = 0

Rewrite

16 y^{2} + 8 y - 24 x + 49 = 0

in the standard form

4 \cdot \frac{3}{8} (x - 2) = (y - (- \frac{1}{4}))^{2}

Therefore parabola properties are:

(h, k) = (2, - \frac{1}{4}), p = \frac{3}{8}

(y - 1)^{2} = 4 (x - 2)

2 y^{2} = 8 b x

4 y^{2} - x - 4 y + 3 = 0

x^{2} - 8 y + 16 = 0

(2 x + y) (2 x - y) = 4 x (x - 1)

What is 16y^2+8y-24x+49=0 ?
The solution to 16y^2+8y-24x+49=0 is Parabola with (h,k)=(2,-1/4),p= 3/8