What is the radius x^2+y^2-6x-10y+18=0 ?

The radius x^2+y^2-6x-10y+18=0 is r=4

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radius x^2+y^2-6x-10y+18=0

radius

r = 4

Solution steps

x^{2} + y^{2} - 6 x - 10 y + 18 = 0

Rewrite

x^{2} + y^{2} - 6 x - 10 y + 18 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 5)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (3, 5), r = 4

And the radius is:

r = 4