What is the radius 2x^2+2y^2-9x-18y-80=0 ?

The radius 2x^2+2y^2-9x-18y-80=0 is r=(sqrt(1045))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

radius 2x^2+2y^2-9x-18y-80=0

radius

r = \frac{1045}{4}

Solution steps

2 x^{2} + 2 y^{2} - 9 x - 18 y - 80 = 0

Rewrite

2 x^{2} + 2 y^{2} - 9 x - 18 y - 80 = 0

in the form of the standard circle equation

(x - \frac{9}{4})^{2} + (y - \frac{9}{2})^{2} = (\frac{1045}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{9}{4}, \frac{9}{2}), r = \frac{1045}{4}

And the radius is:

r = \frac{1045}{4}

What is the radius 2x^2+2y^2-9x-18y-80=0 ?
The radius 2x^2+2y^2-9x-18y-80=0 is r=(sqrt(1045))/4