What is the radius (x+1/2)^2+(y-4/5)^2= 9/4 ?

The radius (x+1/2)^2+(y-4/5)^2= 9/4 is r= 3/2

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radius (x+1/2)^2+(y-4/5)^2= 9/4

radius

r = \frac{3}{2}

Solution steps

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

Rewrite

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

in the form of the standard circle equation

(x - (- \frac{1}{2}))^{2} + (y - \frac{4}{5})^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{2}, \frac{4}{5}), r = \frac{3}{2}

And the radius is:

r = \frac{3}{2}

What is the radius (x+1/2)^2+(y-4/5)^2= 9/4 ?
The radius (x+1/2)^2+(y-4/5)^2= 9/4 is r= 3/2