What is the radius 4x^2+4y^2+40x-32y=5 ?

The radius 4x^2+4y^2+40x-32y=5 is r= 13/2

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radius 4x^2+4y^2+40x-32y=5

radius

r = \frac{13}{2}

Solution steps

4 x^{2} + 4 y^{2} + 40 x - 32 y = 5

Rewrite

4 x^{2} + 4 y^{2} + 40 x - 32 y = 5

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 4)^{2} = (\frac{13}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 5, 4), r = \frac{13}{2}

And the radius is:

r = \frac{13}{2}

What is the radius 4x^2+4y^2+40x-32y=5 ?
The radius 4x^2+4y^2+40x-32y=5 is r= 13/2