What is the radius (x+2)^2+(y+3)^2=9 ?

The radius (x+2)^2+(y+3)^2=9 is r=3

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radius (x+2)^2+(y+3)^2=9

radius

r = 3

Solution steps

(x + 2)^{2} + (y + 3)^{2} = 9

Rewrite

(x + 2)^{2} + (y + 3)^{2} = 9

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 3))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 3), r = 3

And the radius is:

r = 3