What is the radius x^2+24x+y^2+10y=-160 ?

The radius x^2+24x+y^2+10y=-160 is r=3

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radius x^2+24x+y^2+10y=-160

radius

r = 3

Solution steps

x^{2} + 24 x + y^{2} + 10 y = - 160

Rewrite

x^{2} + 24 x + y^{2} + 10 y = - 160

in the form of the standard circle equation

(x - (- 12))^{2} + (y - (- 5))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 12, - 5), r = 3

And the radius is:

r = 3

What is the radius x^2+24x+y^2+10y=-160 ?
The radius x^2+24x+y^2+10y=-160 is r=3