What is the radius x^2+y^2-8x-6y-11=0 ?

The radius x^2+y^2-8x-6y-11=0 is r=6

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radius x^2+y^2-8x-6y-11=0

radius

x^{2} + y^{2} - 8 x - 6 y - 11 = 0

r = 6

Solution steps

x^{2} + y^{2} - 8 x - 6 y - 11 = 0

Rewrite

x^{2} + y^{2} - 8 x - 6 y - 11 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - 3)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (4, 3), r = 6

And the radius is:

r = 6

5 x^{2} + 5 y^{2} + 10 x - 20 y = 55

(x - 1)^{2} + y^{2} = 1

2 x^{2} + 2 y^{2} = 50

x^{2} + y^{2} = 7

\frac{x ^{2}}{49} + \frac{y ^{2}}{49} = 1