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Beliebt Geometry >

center x^2+y^2-16x-14y+31=0

Lösung

center

x^{2} + y^{2} - 16 x - 14 y + 31 = 0

Lösung

(8, 7)

Schritte zur Lösung

x^{2} + y^{2} - 16 x - 14 y + 31 = 0

Rewrite

x^{2} + y^{2} - 16 x - 14 y + 31 = 0

in the form of the standard circle equation

(x - 8)^{2} + (y - 7)^{2} = (82)^{2}

Therefore the circle properties are:

(a, b) = (8, 7), r = 82

And the center is:

(8, 7)

Graph

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