What is the center (x+2)^2+(y-sqrt(5))^2=7 ?

The center (x+2)^2+(y-sqrt(5))^2=7 is (-2,sqrt(5))

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center (x+2)^2+(y-sqrt(5))^2=7

center

(- 2, 5)

Solution steps

(x + 2)^{2} + (y - 5)^{2} = 7

Rewrite

(x + 2)^{2} + (y - 5)^{2} = 7

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 5)^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 5), r = 7

And the center is:

(- 2, 5)

What is the center (x+2)^2+(y-sqrt(5))^2=7 ?
The center (x+2)^2+(y-sqrt(5))^2=7 is (-2,sqrt(5))