What is the center (x-0)^2+(y-0)^2=25 ?

The center (x-0)^2+(y-0)^2=25 is (0,0)

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center (x-0)^2+(y-0)^2=25

center

(x - 0)^{2} + (y - 0)^{2} = 25

(0, 0)

Solution steps

(x - 0)^{2} + (y - 0)^{2} = 25

Rewrite

(x - 0)^{2} + (y - 0)^{2} = 25

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 5

And the center is:

(0, 0)

x^{2} + (y - 1)^{2} = 4

x^{2} + y^{2} + 8 y = 2 x + 20

x^{2} - 2 x + y^{2} - 2 y = 23

13^{2} = (x - (- 4))^{2} + (y - (- 3))^{2}

(x + 3)^{2} + y^{2} = 25