What is the center (x+4)^2+(y-2)^2=121 ?

The center (x+4)^2+(y-2)^2=121 is (-4,2)

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center (x+4)^2+(y-2)^2=121

center

(- 4, 2)

Solution steps

(x + 4)^{2} + (y - 2)^{2} = 121

Rewrite

(x + 4)^{2} + (y - 2)^{2} = 121

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 2)^{2} = 1 1^{2}

Therefore the circle properties are:

(a, b) = (- 4, 2), r = 11

And the center is:

(- 4, 2)

What is the center (x+4)^2+(y-2)^2=121 ?
The center (x+4)^2+(y-2)^2=121 is (-4,2)