What is the center ((x+2)^2)/(16)+((y+5)^2)/(16)=1 ?

The center ((x+2)^2)/(16)+((y+5)^2)/(16)=1 is (-2,-5)

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center ((x+2)^2)/(16)+((y+5)^2)/(16)=1

center

(- 2, - 5)

Solution steps

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 5))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 5), r = 4

And the center is:

(- 2, - 5)

What is the center ((x+2)^2)/(16)+((y+5)^2)/(16)=1 ?
The center ((x+2)^2)/(16)+((y+5)^2)/(16)=1 is (-2,-5)