What is the center (x-4)^2+(y-1)^2=218 ?

The center (x-4)^2+(y-1)^2=218 is (4,1)

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center (x-4)^2+(y-1)^2=218

center

(x - 4)^{2} + (y - 1)^{2} = 218

(4, 1)

Solution steps

(x - 4)^{2} + (y - 1)^{2} = 218

Rewrite

(x - 4)^{2} + (y - 1)^{2} = 218

in the form of the standard circle equation

(x - 4)^{2} + (y - 1)^{2} = (218)^{2}

Therefore the circle properties are:

(a, b) = (4, 1), r = 218

And the center is:

(4, 1)

4 x^{2} + 4 y^{2} - x + 2 y - 11 = 0

(x + 2)^{2} + (y - 3)^{2} = 5

X^{2} + Y^{2} + 40 X - 10 Y + 55 = 0

x^{2} + y^{2} + 6 x - 4 y - 5 = 0

(x + 2)^{2} + (y + 3)^{2} = 81

What is the center (x-4)^2+(y-1)^2=218 ?
The center (x-4)^2+(y-1)^2=218 is (4,1)