What is the center (x-1.5)^2+(y+0.5)^2=110.5 ?

The center (x-1.5)^2+(y+0.5)^2=110.5 is (1.5,-0.5)

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center (x-1.5)^2+(y+0.5)^2=110.5

center

(x - 1.5)^{2} + (y + 0.5)^{2} = 110.5

(1.5, - 0.5)

Solution steps

(x - 1.5)^{2} + (y + 0.5)^{2} = 110.5

Rewrite

(x - 1.5)^{2} + (y + 0.5)^{2} = 110.5

in the form of the standard circle equation

(x - 1.5)^{2} + (y - (- 0.5))^{2} = 10.51189 \dots^{2}

Therefore the circle properties are:

(a, b) = (1.5, - 0.5), r = 10.51189 \dots

And the center is:

(1.5, - 0.5)

(x - 7)^{2} + (y + 4)^{2} = 9

x^{2} + y^{2} - 6 x - 8 y + 9 = 0

(x + 2)^{2} + (y - 4)^{2} = 16

x^{2} + y^{2} - 8 x + 4 y + 11 = 0

x^{2} + y^{2} - 6 y = 16

What is the center (x-1.5)^2+(y+0.5)^2=110.5 ?
The center (x-1.5)^2+(y+0.5)^2=110.5 is (1.5,-0.5)