de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

center 2(x-2)^2+2y^2=2

Lösung

center

2 (x - 2)^{2} + 2 y^{2} = 2

Lösung

(2, 0)

Schritte zur Lösung

2 (x - 2)^{2} + 2 y^{2} = 2

Rewrite

2 (x - 2)^{2} + 2 y^{2} = 2

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 1

And the center is:

(2, 0)

Graph

Beliebte Beispiele

center (x-4)^2+(y-5)^2=36

ce n t er (x - 4)^{2} + (y - 5)^{2} = 36

center x^2-8x+y^2-2y+8=0

ce n t er x^{2} - 8 x + y^{2} - 2 y + 8 = 0

center x^2+y^2-2x+3y-1=0

ce n t er x^{2} + y^{2} - 2 x + 3 y - 1 = 0

center x^2+y^2-4x+6y+9=0

ce n t er x^{2} + y^{2} - 4 x + 6 y + 9 = 0

center x^2+y^2+2x-2y-2=0

ce n t er x^{2} + y^{2} + 2 x - 2 y - 2 = 0