What is 2x^2-29x-65+225r(x)=0 ?

The solution to 2x^2-29x-65+225r(x)=0 is Parabola with (h,k)=(29/4 , 1361/1800),p=-225/8

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2x^2-29x-65+225r(x)=0

2 x^{2} - 29 x - 65 + 225 r (x) = 0

(h, k) = (\frac{29}{4}, \frac{1361}{1800}), p = - \frac{225}{8}

Solution steps

2 x^{2} - 29 x - 65 + 225 y = 0

Rewrite

2 x^{2} - 29 x - 65 + 225 y = 0

in the standard form

4 (- \frac{225}{8}) (y - \frac{1361}{1800}) = (x - \frac{29}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{29}{4}, \frac{1361}{1800}), p = - \frac{225}{8}

x^{2} - 2 x - 6 y - 5 = 0

y^{2} = - 3 (x - 1)

x^{2} - 12 x - 12 y + 96 = 0

9 - 3 x = 7 y^{2} + 5 x

x = 5 (y - 1)^{2}

What is 2x^2-29x-65+225r(x)=0 ?
The solution to 2x^2-29x-65+225r(x)=0 is Parabola with (h,k)=(29/4 , 1361/1800),p=-225/8